Category : Recently Uploaded Files
Archive : DCSOLVE.ZIP
Filename : WIRE.BAS
Output of file : WIRE.BAS contained in archive : DCSOLVE.ZIP
BF« I N M Yí XM .098 Q C LOCAT2. L H5 XC Za XQ TT K AGA TAú TBF R= NAWROè FIN A CIR PR START1\STARTjOKREP&STu XX DEAF CHG SNDF RIGHTVNOS SETUP C1 So BEGIN D LE{ LL LIE INE XL IFXL LF L2
! sd%ç eP e+ ø s£ * ÿÿÀ }B e
de1 Ó de6 Ó d e. Ó dd
e{e[ e ¼ d
d e sÐ dx 5 Y M d) + d) ( . Vá , de
V ÿÿò e ÿÿ ¦ de
V ÿÿ> ¦ e
dDp&d í e ÿÿ d ô Êú ô t f d; d d ± m .004d Ô mA A PIECE OF WIRE HAS A RESISTANCE OF .028ê. WHAT IS THE RESISTANCE"d mD OF AN EQUAL LENTGH WIRE WHICH HAS TWICE THE DIAMETER OF THE FIRST ? d m" USING RESISTIVITY EQUATION, R = ? d è d ; d d ± m .06"d Ô m? A PIECE OF WIRE HAS A RESISTANCE OF .12ê. IF THE WIRE IS CUT IN"d m# HALF, WHAT IS THE NEW RESISTANCE ? "d m" USING RESISTIVITY EQUATION, R = ? d è d
; d
d
± m 10.4d Ô m 16380"d Ô m .128d
Ô m? THE COPPER CABLE OF AN AUTOMOBILE STARTER MOTOR HAS A LENTGH OF"d mI 3.15 FT. TESTING OF THE SYSTEM INDICATES THAT THE CABLE RESISTANCE SHOULD"d m< BE NO MORE THAN .002ê. WHAT MINIMUM DIAMETER IS NECESSARY ? d
m8 FIND AREA A = KL / R 16380 CM =(?)(3.15) / .002 d è m
D(MILS) = eû m
A m 128 MILS = " eû m ? d è m DIAMETER IN INCHES = ? "d
è d; d j d ± m 92d Ô m 9.057"d Ô m 9"d
Ô m Y"d Ô m FIND THE LOAD VOLTAGE ELd m 230V o m LOAD u m 9ê { m #8 CU 46FT m: FROM TABLE 2 R(WIRE) = .057ê = (.628ê / 1000FT) x ? d è m' USING OHNS LAW I = 25.4A = 230 / ? "d è m EL = 228.6V = 25.4 x ? "d
è m) DO YOU THINK THE WIRE SIZE IS OK (Y/N) ? "d è d; d
d
± m .4d Ô m 250"d Ô m 12d
Ô m; IT IS DESIRED TO DRIVE A 40ê HEATER THROUGH A 125 FT COPPER"d mF EXTENSION CORD. TO MAKE THE CORD VOLTAGE DROP NEGLIBLE, ITS RESISTANCEd mE SHOULD BE LESS 1% OF THE LOAD RESISTANCE. WHAT GAUGE WIRE IS NEEDED ?"d
m2 FIND WIRE RESISTANCE R(WIRE) = .01 x 40 = ? d è m6 FIND AREA A = KL / R 6500 CM = (10.4)(?) / .4 d è m FROM TABLE 2 GAUGE # = ? d
è d; d
d
± m 100"d Ô m 2080d Ô m 16d
Ô mB A 50FT COPPER EXTENSION CORD IS REQUIRED TO OPERATE A DRILL MOTOR.d mI BASED UPON THE CURRENT NEEDED TO RUN THE DRILL MOTOR, THE CORD RESISTANCE"d m7 CANNOT NOT EXCEED .5ê. WHAT GAUGE WIRE SHOULD BE USED ?"d
m6 FIND AREA A = KL / R 2080 CM = (10.4)(?) / .5 d è m
D(MILS) = eû m
A m
46 MILS = eû m ? d è m FROM TABLE 2, GAUGE = ? d
è d ; d d ± m 16.1d Ô m8 WHAT LENTGH OF #22 COPPER WIRE HAS A RESISTANCE OF 1ê ? d m4 FROM TABLE 2, LENTGH = (1000 FT / ?) x 1ê = 62.1 FT d è d!; d d ± m 100"d Ô mC WHAT LENTGH OF #30 ALUMINUM WIRE IS NEEDED TO MAKE A 30ê RESISTOR ?"d m. L = RA / K 176.4 FT = (30)(?) / 17 d è d%; d d ± m NICKELd Ô m@ CONSIDERING THE TEMPERATURE COEFFECIENT OF THE MATERIALS LISTED,d m; WHICH MATERIAL WOULD MAKE THE BEST RESISTANCE THERMOMETER ?"d m! FROM TABLE 1, BEST MATERIAL IS ? "d è d); d d ± d j m 220V o m MOTOR" u m 198V, 13A" { m #14 CU COPPER m 11d Ô m 10.4d Ô mC FIND MAXIMUM DISTANCE THE MOTOR CAN BE PLACED FROM THE 220V SOUCRE."d m9 FIND RESISTANCE OF 1 LINE R = E / I .85ê = ? / 13 "d è m, L = RA / K 334 FT = (.85)(4096) / ? d è e ; d d ± m 3"d Ô m6 WHAT IS THE RESISTANCE OF 36 INCHES OF #22 GOLD WIRE ?d m, R = KL / A .07ê = (14.7)(?) / 625 d è e ; d
d
± m 114"d Ô m 6"d Ô m 1000d
Ô m@ A 2-WIRE COPPER FEEDER LINE IS TO SUPPLY A 1500 WATT LOAD 500 FTd m@ AWAY FROM A 120V SOURCE. WHAT MINIMUM WIRE AREA IS REQUIRED IF Ad m. 5% VOLTAGE DROP CAN BE TOLERATED AT THE LOAD ?d
m0 FIND CURRENT I = P / E 13.3A = 1500 / ? d è m- FIND R(WIRE) R = E / I .54ê = ? / 13.3 "d è m- A = KL / R 19259 CM = (10.4)(?) / .54 "d
è e
; d d ± m NICHROMEd Ô m 1600d Ô m: A 50 FT PIECE OF WIRE HAS A DIAMETER OF .04 INCHES. IF ITSd m7 RESISTANCE MEASURES 20.25ê, WHAT IS THE WIRE MATERIAL ?"d m' K = RA / L 648 = (20.25)(?) / 50 "d è m FROM TABLE 1, MATERIAL IS ? d è R se ¤ se sd
Á m PROBLEM :" se ¤ se se
Á d se sd
Á d se sd
Á d
d] Be « d ] Xe « d
] ne « jda 6 e « d j m BM185,195" ª se se Á o se se5 Á u se se= Á { se se Á e deÄ S deÄ S e P sd¤ s « sd Á m
SOLUTION : k d ± V ÿÿ¢ · dd
V ÿÿB se ¤ s « se Á k m ) k è Ã dA É sd¤ m Ï ¶ Ï k Ô ] Y
Y Ú s à s É Á d e ÿÿ · d] s à s É d Á sd¤ k Ô æ « d « e ÿÿ îá sd)¤ se( se Á m ANOTHER PROBLEM (Y/N)" d" è m YN è $d] [ á è m N"] &s£ î a dd
V ÿÿd m a m a Ô e ÿÿ d ± d e eveM d¼ ô d ô ô e ] ¬[ [ ú N 4Ú 5d] Î[ m MBÖ m T200 O1 L4 C. P16 L8D L4 E-CÖ Ø s « d se# Á · d] 6m TRY AGAIN" · d ] Vm LAST CHANCE" · d
] tm INCORRECT" d { s « d se# Á e o ø.' 5d nx 5 o .
5d] Ö[ F m T255 O2 L16 CEG O3 CEGÖ :F p ÿÿM sd¤ sd
se Á m RESISTANCE DETERMING FACTORS sdse Á e" eÍ S se ¤ sdsdÁ mI THIS PROGRAM DEALS WITH THE VARIOUS PARAMETERS THAT EFFECT THE RESISTANCE" sd!sdÁ mD OF A MATERIAL AND IN PARTICULAR WIRE RESISTANCE. THESE FACTORS ARE : sd)se Á m 1) LENTGH OF MATERIAL" se se Á m 2) CROSS SECTIONAL AREA" se se Á m% 3) RESISTIVITY OF A SPECIFIC MATERIAL" se sdÁ mE PROBLEM SOLUTIONS REQUIRE USE OF THE RESISTIVITY EQUATION AND THE AWG" se sdÁ mE WIRE TABLES. THE UNKNOWS FOR EACH PROBLEM ARE INDICATED BY A QUESTION" se sdÁ m> MARK. AT THE PROMPT, TYPE IN YOUR ANSWER AND THEN PRESS ENTER. sd¤ se se Á m, TO TOGGLE SOUND OFF\ON AT ANY TIME, PRESS F1 sd)¤ se se Á m PRESS ANY KEY TO BEGIN d" V d%d eve d¼ sd¤ sd se Á m TABLE 1 - RESISTIVITY" sd se1 Á m TABLE 2 - COPPER WIRE" se ¤ sdsdÁ m MATERIAL sdse Á m K" sdse Á m TEMP. COEFF. sdse- Á m B & S" sdse6 Á m DIAMETER sdse Á m ê/MIL-FT sdse Á m
OF RESISTANCE" sdse- Á m GAUGE" sdse8 Á m MILS sdseB Á m ê / 1000 FT" m# C1R250D10L30D15R60U15L30BD15D10L250" mF ALUMINUM 17 .004 0 325 .098 d f mE BRASS 44 .002 8 128 .628"d f mE COPPER 10.4 .004 12 81 1.588"d
f mE NICKEL 42.1 .006 14 64 2.525"d f mE NICHROME 648 .00017 16 51 4.016"d f mE SILVER 9.77 .0038 18 40 6.390"d f mE GOLD 14.7 .0034 22 25 16.100"d f mE BRONZE 108 .0005 30 10 103.200"d! f d u k d e V ÿÿX s k sdÁ u f u d u e ÿÿ m5 C15BM13,19R300D100L300U100BR87D100BR86U100BM13,43R300"ª m7 C15BM327,19R300D100L300U100BR87D100BR86U100BM327,43R300"ª sd)¤ se se Á m R = se se Á m K x L" se se Á m A" ek e e e d)¼ se se Á m L = LENTGH IN FT se se2 Á m A(CIR MILS) = D(MILS)"eý se ¤ o ´ ÿÿÿÿÌ
Very nice! Thank you for this wonderful archive. I wonder why I found it only now. Long live the BBS file archives!
This is so awesome! 😀 I’d be cool if you could download an entire archive of this at once, though.
But one thing that puzzles me is the “mtswslnkmcjklsdlsbdmMICROSOFT” string. There is an article about it here. It is definitely worth a read: http://www.os2museum.com/wp/mtswslnk/